# Free Construction and Skilled Trades Practice Test

## Mechanical Concepts

**1. Objects 1 and 2 are submerged in separate tanks, both filled with water. In which tank (A or B) will the water level be the highest? (If equal, mark C)**

**2. If ball 1 and ball 2 are of equal weight and moving at the same speed, in which direction (A, B, or C) will ball 1 tend to go when it collides with ball 2 at point X?**

**3. In which direction (A or B) will gear 5 spin if gear 1 is spinning counter-clockwise? (If both, mark C)**

**4. Which of the two identical objects (A or B) will launch a higher distance when the springs are released? (If equal, mark C)**

## Answers

**
1.** B

**
2.** A

**
3.** A

**
4.** B

## Graphic Arithmetic

**1. What is the distance ("A") from the left edge of the property to the break room?**

- 47'
- 67'
- 70'
- 19'
- N

**2. What is the distance ("B") from the top edge of the property to the conference room?**

- 57'
- 22'
- 27'
- 59'
- N

**3. What is the distance ("C") from the bottom of the property to the employee office?**

- 19'
- 60'
- 10'
- 18'
- N

**4. What is the area of the manager's office?**

- 44 ft2
- 480 ft2
- 360 ft2
- 576 ft2
- N

Answers

**1. C:**70'. To find the unknown distance ("A"), subtract the known widths from the total width of the property. The total width of the property is 117'. The other known widths are 20' and 27'. To find A, subtract 20' and 27' from 117'. A + 20' + 27' = 117'. A = 117' - 20' - 27' = 70'.- .
**B: 22'.**To find the unknown length ("B"), subtract the known lengths from the total length of the property. The total length of the property is 79'. The known lengths are 37' and 20'. To find B, subtract 37' and 20' from 79'. B + 20' + 37' = 79'. B = 79' - 20' - 37' = 22'. **3. A:**19'. To find the unknown length ("C"), subtract the known lengths from the total length of the property. The total length of the property is 79'. The known lengths are 18', 18', and 24'. To find C, subtract 18', 18', and 24' from 79'. C + 18' + 18' + 24' = 79'. C = 79' - 18' - 18' - 24' = 19'.**4. B: 480 ft2.**To find the area of the manager's office, multiply the length of the office by the width of the office. The length of the office is 24'. The width of the office is 20'. Area of the manager's office = 24' - 20' = 480 ft2.

## Mathematical Usage

Answer the following questions based on this information:

1 foot = 12 inches

1 gallon = 3.785 liters

1 gallon = 4 quarts

1 inch = 2.54 centimeters

1 kilogram = 1,000 grams

1 kilogram = 2.2 pounds

1 kilometer = 1,000 meters

1 mile = 1.609 kilometers

1 mile = 5,280 feet

3 mile/hour = 4.4 feet/second

1 pound = 16 ounces

1 quart = 2 pints

1 square mile = 640 acres

**1. 2 miles = ? kilometers**

- 1.609
- 3.218
- 1.243
- 2.486

**2. 3 quart = ? gallons**

- 0.33
- 4
- 1.33
- 0.75

**3. 8 quarts = ? liters**

- 7.57
- 121.12
- 15.14
- 0.53

**4. 5 feet = ? centimeters**

- 12.7
- 23.6
- 152.4
- 60

Answers

- B: 3.218 kilometers
- D: 0.75 gallons
- A: 7.57 liters
- C: 152.4 centimeters

## CAST Math Practice Test

Last Updated: 10/11/2017