Free CLEP College Math Exam Practice Questions

1. Two complex numbers a + ib and c + id are identical
  1. if a and b are equal
  2. if and only if c and d are equal
  3. if and only if a = c and b = d
  4. if and only if a = b and c = d
2. The set A = {0, 2, 4, 6, 8} and the set B = {1, 3, 5, 7}. Which of the following is not a member of the set A X B?
  1. (4,3)
  2. (1,2)
  3. (2,1)
  4. (6,1)
3. The number of elements in the set A = 1,232, in set B = 4,376 and in set C = 3,128. Some elements of A are also found in B and C, and some are found in all of A, B and C. The number of unique, or unshared, elements in the set A U B U C is
  1. 8,736
  2. nA + nB + nC − n(A ∩ B) − n(A ∩ C) − n(B ∩ C)
  3. nA + nB + nC − n(A ∩ B) − n(A ∩ C) − n(B ∩ C) − n(A ∩ B ∩ C)
  4. nA + nB + nC − n(A ∩ B) − n(A ∩ C) − n(B ∩ C) + n(A ∩ B ∩ C)
4. In a group of 48 people, 1/3 claimed to be Christians, 3/16 were followers of Islam, 1/16 were Buddhists, 1/16 were Hindu, 1/48 were Sikh, 1/12 were traditional Native Americans and the remainder claimed no religious affiliation. The number of individuals in each group was
  1. 12, 4, 1, 3, 3, 9, 16
  2. 16, 9, 3, 3, 1, 4, 12
  3. 12, 1, 4, 3, 3, 9, 16
  4. none of the above
5. A magician has a hat that holds two rabbits. One rabbit is black and the other is white. In his last 16 performances he has randomly pulled the black rabbit from the hat 16 times. The probability that he will pull the white rabbit from the hat in his next performance is
  1. 0.50
  2. 1
  3. 1/17
  4. 0
6. A bag contains 16 coins, each with a different date. The number of possible combinations of three coins from the bag is
  1. 650
  2. 48
  3. 560
  4. 6
7. Ten sample values were found to be 6, 7, 7, 9, 5, 7, 8, 2, 6 and 3. The mean and median values of these samples are
  1. 6 and 6.5
  2. 6 and 7
  3. 6 and 8
  4. 6.5 and 7
8. Seven samples were obtained having the values 21, 22, 26, 29, 27, 26 and 24. The mean and standard deviation values are
  1. 22.4 and 2.6
  2. 25 and 2.2
  3. 25 and 2.6
  4. 25.6 and 2.2
9. The factors (x − 3), (x − 4) and (x + 7) expand to give the equation
  1. x3 − 12x2 -7x + 84
  2. x3 + 84x2 − 14x + 14
  3. x3 − 37x + 84
  4. x3 + 14x2 − 7x + 84
10. When multiplied together the two complex numbers (6 + i5) and (3 − i3) yield
  1. (18 − i15)
  2. (33 − i3)
  3. (33 − i9)
  4. (33 − i15)