Comparison Math Problems

Solving the system of equations gives \(y = -4.5\). Since -4.5 is greater than -5, Quantity A is greater.

First, we need to determine the sum of the angles shown in the figure. These are all central angles of a circle, and in this case, they together form a complete circle. A full circle contains 360°, so we can say:

\(v+w+x+y+z=360°\)

The average of five values is the sum divided by 5:

\(\dfrac{360°}{5}=72°\)

This tells us that Quantity A is 72°, which means it is larger than Quantity B.

The shaded area comprises a total angle measure that may be represented as:

\(0.65 \times 360° = 234°\)

Thus, the non-shaded area, which represents the value of \(d\), is equal to the difference of 360° and 234°, which is 126°. This value is the same value given for Quantity B.

The area of a circle with a radius of 3 is equal to 9\(\pi\). The area of a semi-circle with a radius of 4 is equal to half of 16\(\pi\), which is 8\(\pi\). Thus, Quantity A is greater.

The problem may be modeled as follows:

\(0.34 \times 360 = 0.075h\)

Solving for \(h\) gives \(h = 1,632\), which is less than 1,634. Thus, Quantity B is greater.

The fraction of 76 hours in a week may be represented by the ratio \(\tfrac{76}{168}\), which is approximately 45%.

The fraction of 10 hours in a day may be represented by the ratio \(\tfrac{10}{24}\), which is approximately 42%.

Thus, Quantity A is greater.

Since the values of \(x\) and \(y\) are the same, the difference will equal 0. Thus, Quantities A and B are equal.

The value for Quantity A may be written as \(5\times 6\). The value for Quantity B may be written as \(6\times 5\). Both expressions equal 30, thus both Quantities A and B are equal.

The value of Quantity A may be written as 0.96\(n\), which is greater than 0.95\(n\). Thus, Quantity A is greater.

The problem may be modeled as \(5 = 0.667n\), where \(n \approx 7.5\).

Since 15 is greater than 7.5, Quantity B is greater.